A three-point scan makes the direct mass-to-heat relationship visible before the formula is compressed. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Hold material and warming fixed

Use one material with specific heat 5 joules per kilogram per kelvin, and warm every sample by 4 kelvin.

Q=mcΔTQ = mc\Delta T
Mass scanThe three heat bars share one joule scale.20 Jsmall40 Jmiddle60 Jlargemass scan

First mass point

The first sample has the smallest mass, so it gets the first row in the scan.

Qfirst=1 kg5 J/(kg K)4 K=20 JQ_{\text{first}} = 1\ \text{kg}\cdot 5\ \text{J/(kg K)}\cdot 4\ \text{K} = 20\ \text{J}

Second mass point

The same material and same warming now act on a larger mass. Only the mass changed.

Qsecond=2 kg5 J/(kg K)4 K=40 JQ_{\text{second}} = 2\ \text{kg}\cdot 5\ \text{J/(kg K)}\cdot 4\ \text{K} = 40\ \text{J}

Third mass point

The third mass makes the direct pattern visible without needing to infer it from two cases.

Qthird=3 kg5 J/(kg K)4 K=60 JQ_{\text{third}} = 3\ \text{kg}\cdot 5\ \text{J/(kg K)}\cdot 4\ \text{K} = 60\ \text{J}

Read the three-point mass scan

With material and warming fixed, mass and heat rise together. The diagram and the table use the same three checked values.

mcΔTQ1 kg5 J/(kg K)4 K20 J2 kg5 J/(kg K)4 K40 J3 kg5 J/(kg K)4 K60 J\begin{array}{c|c|c|c}m&c&\Delta T&Q\\1\ \text{kg}&5\ \text{J/(kg K)}&4\ \text{K}&20\ \text{J}\\2\ \text{kg}&5\ \text{J/(kg K)}&4\ \text{K}&40\ \text{J}\\3\ \text{kg}&5\ \text{J/(kg K)}&4\ \text{K}&60\ \text{J}\\\end{array}
Mass scanThe three heat bars share one joule scale.20 Jsmall40 Jmiddle60 Jlargemass scan