Repeatedly find the index of the smallest remaining element and swap it into the next "sorted prefix" slot. Unlike bubble sort, only one swap per pass.

Algorithm

Canonical input [5, 1, 4, 2, 8] finishes after four passes, with two real swaps (passes 0 and 1) and two skip-swap passes (minIdx == i). Final array [1, 2, 4, 5, 8].

Basic Implementation

basic.go
package main

import "fmt"

func main() {
	arr := []int{5, 1, 4, 2, 8}
	n := len(arr)
	for i := 0; i < n-1; i++ {
		minIdx := i
		for j := i + 1; j < n; j++ {
			if arr[j] < arr[minIdx] {
				minIdx = j
			}
		}
		if minIdx != i {
			arr[i], arr[minIdx] = arr[minIdx], arr[i]
		}
	}
	fmt.Println(arr)
}

Complexity

  • Time: O(n^2) regardless of input order
  • Space: O(1)
  • Stable: no
  • Swap count: at most n-1

Implementation notes

  • Go: same loop shape as Python / Java / JavaScript / C++ / C. The if minIdx != i guard is the canonical skip-swap variant from the lesson spec.
  • minIdx := i keeps the running-minimum invariant visible; the tuple swap arr[i], arr[minIdx] = arr[minIdx], arr[i] mirrors the bubble-sort lesson.
  • The replay highlights the current minIdx distinctly from the scanning index j so the viewer sees the running minimum travel.
running minimum `minIdx` tracks the index of the smallest value seen in `arr[i..]`.
sorted prefix After each pass, `arr[0..i]` is the final sorted prefix.