Walk an array once looking for a target value. Return the index of the first match, or -1 if none. The simplest possible search loop.

Algorithm

Canonical input arr = [4, 7, 1, 9, 3, 8] with target = 9 finishes after four compares; the matching index is 3.

early exit Return the index the moment `arr[i]` equals the target. Walking past it would defeat the point.
sentinel return A no-match walk falls off the loop and returns `-1`.

Basic Implementation

basic.go
Replay: real traced execution (multi-file project)
package main

import "fmt"

func linearSearch(arr []int, target int) int {
	for i := 0; i < len(arr); i++ {
		if arr[i] == target {
			return i
		}
	}
	return -1
}

func main() {
	arr := []int{4, 7, 1, 9, 3, 8}
	target := 9
	result := linearSearch(arr, target)
	fmt.Println(result)
}
  1. arr ← [4, 7, 1, 9, 3, 8]

    14func main() {15	arr := []int{4, 7, 1, 9, 3, 8}16	target := 9
    values this step[4, 7, 1, 9, 3, 8]arr
  2. target ← 9

    15arr := []int{4, 7, 1, 9, 3, 8}16target := 917result := linearSearch(arr, target)
    values this step9target[4, 7, 1, 9, 3, 8]arr
  3. result ← -1

    16target := 917result := linearSearch(arr, target)18fmt.Println(result)
    values this step-1result9target
  4. match ← no

    6for i := 0; i < len(arr); i++ {7	if arr[i] == target {8		return i
    values this stepnomatch0i4arr[i]9target
  5. match ← no

    6for i := 0; i < len(arr); i++ {7	if arr[i] == target {8		return i
    values this stepnomatch1i7arr[i]9target
  6. match ← no

    6for i := 0; i < len(arr); i++ {7	if arr[i] == target {8		return i
    values this stepnomatch2i1arr[i]9target
  7. match ← yes

    6for i := 0; i < len(arr); i++ {7	if arr[i] == target {8		return i
    values this stepyesmatch3i9arr[i]9target
  8. result ← 3

    7if arr[i] == target {8	return i9}
    values this step3result3i
  9. stdout ← 3

    17	result := linearSearch(arr, target)18	fmt.Println(result)19}
    values this step3stdout3result

Complexity

  • Time: O(n)
  • Space: O(1)

Implementation notes

  • Go: explicit for i := 0; i < len(arr); i++ with an early return i the moment arr[i] == target. The standard slices.Index would hide the walk the lesson is teaching.
  • Function signature func linearSearch(arr []int, target int) int documents the integer-slice contract; the -1 sentinel mirrors the language-neutral spec.
  • The replay shows the running index, the element being checked, and a match indicator on each frame.