Graphs
Shortest Path (Unweighted, via BFS)
BFS explores a graph layer by layer, so the first time it reaches a vertex is along a shortest path. Track distance and predecessor while exploring, then walk predecessors back from the target to reconstruct the route.
Algorithm
On the canonical graph from graph-adjacency-list, the shortest path from
1 to 6 is 1 2 4 5 6 (space-separated) with distance 4. The path is rebuilt from the predecessor
of each vertex: 6 -> 5 -> 4 -> 2 -> 1, reversed.
Basic Implementation
basic.f90
program graph_shortest_path
implicit none
integer, parameter :: N = 6
integer :: adj(N, 3) = 0
integer :: adj_len(N)
integer :: dist(N)
integer :: parent(N)
integer :: queue(N)
integer :: path(N)
integer :: head, tail, src, dst, v, i, nb, node, path_count
adj_len = [2, 2, 2, 3, 2, 1]
adj(1, 1:2) = [2, 3]
adj(2, 1:2) = [1, 4]
adj(3, 1:2) = [1, 4]
adj(4, 1:3) = [2, 3, 5]
adj(5, 1:2) = [4, 6]
adj(6, 1:1) = [5]
src = 1
dst = 6
dist = -1
parent = 0
dist(src) = 0
queue(1) = src
head = 1
tail = 1
do while (head <= tail)
v = queue(head)
head = head + 1
do i = 1, adj_len(v)
nb = adj(v, i)
if (dist(nb) == -1) then
dist(nb) = dist(v) + 1
parent(nb) = v
tail = tail + 1
queue(tail) = nb
end if
end do
end do
path_count = 0
node = dst
do while (node /= 0)
path_count = path_count + 1
path(path_count) = node
node = parent(node)
end do
print '(*(I0,1X))', (path(i), i = path_count, 1, -1)
print '(I0)', dist(dst)
end program graph_shortest_path
Complexity
- Time: O(V + E)
- Space: O(V)
Implementation notes
- Fortran:
distinitialised to -1 doubles as the visited check,parentrecords predecessors (0 marks the source), and a ring of indices overqueuegives FIFO order. - The replay shows the distances and predecessors filling in, then the reconstructed path, matching the lesson spec.
layers equal distance
BFS order equals distance in an unweighted graph.