Displaced volume drives apparent weight down to the float threshold. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Small displacement leaves eighty newtons

Displaced volume V=1 cubic metre gives buoyant force 20 newtons. From weight 100 newtons, the support reads 80 newtons.

10020=80100 - 20=80
Buoyancy volume scanDisplacement and apparent weight are checked together.bodyBWrho=2 kg/m^3g=10 m/s^2V=1 m^3B=20 NW=100 NWapp=80 N

More displaced fluid lowers the reading

Displaced volume V=3 cubic metres gives buoyant force 60 newtons. From weight 100 newtons, the support reads 40 newtons.

10060=40100 - 60=40
Buoyancy volume scanDisplacement and apparent weight are checked together.bodyBWrho=2 kg/m^3g=10 m/s^2V=3 m^3B=60 NW=100 NWapp=40 N

At full balance the support reads zero

Displaced volume V=5 cubic metres gives buoyant force 100 newtons. From weight 100 newtons, the support reads 0 newtons.

100100=0100 - 100=0
Buoyancy volume scanDisplacement and apparent weight are checked together.bodyBWrho=2 kg/m^3g=10 m/s^2V=5 m^3B=100 NW=100 NWapp=0 N