Fluid Relation Cross Scans

Buoyancy Apparent Weight Three-Row Scan

A buoyancy-apparent-weight scan varies displaced volume across three rows, showing how the buoyant force F_b = rho * g * V reduces the apparent weight row by row. The arithmetic is exact only for the stated densities, displaced volumes, and rows in the ideal buoyancy model. Real fluids add viscosity, turbulence, compressibility, geometry tolerance, calibration, and measurement uncertainty.

Displaced volume and object weight set the support reading. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Small displacement leaves forty newtons

Volume 2 cubic metres displaces buoyancy 40 newtons. Weight 80 newtons leaves apparent weight 40 newtons.

Wapp=80−40=40W_{\mathrm{app}}=80 - 40=40
Buoyancy scan rowBuoyant force and apparent weight are checked.bodybuoyweightrho=2 kg/m^3g=10 m/s^2V=2 m^3B=40 NW=80 NWapp=40 N

More displacement leaves ten newtons

Volume 3 cubic metres displaces buoyancy 60 newtons. Weight 70 newtons leaves apparent weight 10 newtons.

Wapp=70−60=10W_{\mathrm{app}}=70 - 60=10
Buoyancy scan rowBuoyant force and apparent weight are checked.bodybuoyweightrho=2 kg/m^3g=10 m/s^2V=3 m^3B=60 NW=70 NWapp=10 N

Heavier object can keep the same reading

Volume 4 cubic metres displaces buoyancy 80 newtons. Weight 90 newtons leaves apparent weight 10 newtons.

Wapp=90−80=10W_{\mathrm{app}}=90 - 80=10
Buoyancy scan rowBuoyant force and apparent weight are checked.bodybuoyweightrho=2 kg/m^3g=10 m/s^2V=4 m^3B=80 NW=90 NWapp=10 N