A buoyancy apparent-volume scan varies displaced volume across three rows, showing how buoyant force and apparent weight shift as rho * g * V changes. The arithmetic is exact only for the stated densities, displaced volumes, weights, and rows in the ideal static-fluid model. Real measurements add viscosity, turbulence, compressibility, pipe/container geometry, calibration, elevation reference, finite precision, and measurement uncertainty.

Displaced volume drives apparent weight down to the float threshold. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Small displacement leaves eighty newtons

Displaced volume V=1 cubic metre gives buoyant force 20 newtons. From weight 100 newtons, the support reads 80 newtons.

100−20=80100 - 20=80
Buoyancy volume scanDisplacement and apparent weight are checked together.bodyBWrho=2 kg/m^3g=10 m/s^2V=1 m^3B=20 NW=100 NWapp=80 N

More displaced fluid lowers the reading

Displaced volume V=3 cubic metres gives buoyant force 60 newtons. From weight 100 newtons, the support reads 40 newtons.

100−60=40100 - 60=40
Buoyancy volume scanDisplacement and apparent weight are checked together.bodyBWrho=2 kg/m^3g=10 m/s^2V=3 m^3B=60 NW=100 NWapp=40 N

At full balance the support reads zero

Displaced volume V=5 cubic metres gives buoyant force 100 newtons. From weight 100 newtons, the support reads 0 newtons.

100−100=0100 - 100=0
Buoyancy volume scanDisplacement and apparent weight are checked together.bodyBWrho=2 kg/m^3g=10 m/s^2V=5 m^3B=100 NW=100 NWapp=0 N