Changing one demand weight moves the balance point exactly.

highlighted = computed this step

Lower C

If C's weight drops from 3 to 1, the center is recomputed.

wC=1w_C=1
Lower C weightChanging one input recomputes the center exactly.C weight lowered03/26014A w=2B w=1C w=1center (3/2, 1)total weight 4x coordinatey

New x

The new center x coordinate is 3/2.

xˉnew=3/2\bar{x}_{new}=3/2
Lower C weightChanging one input recomputes the center exactly.C weight lowered03/26014A w=2B w=1C w=1center (3/2, 1)total weight 4x coordinatey

New y

The new center y coordinate is 1.

yˉnew=1\bar{y}_{new}=1
Lower C weightChanging one input recomputes the center exactly.C weight lowered03/26014A w=2B w=1C w=1center (3/2, 1)total weight 4x coordinatey

What-if meaning

With less weight at C, the marker moves down and right to (3/2, 1).

new center=(3/2,1)\text{new center}=(3/2,1)
Lower C weightChanging one input recomputes the center exactly.C weight lowered03/26014A w=2B w=1C w=1center (3/2, 1)total weight 4x coordinatey