A voltage divider uses two resistor drops to make a node voltage. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

A divider is two resistors in series

The output node sits between the top resistor and the bottom resistor.

output node is between the two drops\text{output node is between the two drops}
Voltage dividerThe output node is the shared node between two resistors.12 V2 ohm4 ohm2 A+-4 V+-8 Vtopoutputbottom

Compute the series current

The source is 12 volts. The resistors are 2 ohm and 4 ohm, so the current is 2 amperes.

I=12 V2 ohm+4 ohm=2 AI = \frac{12\ \text{V}}{2\ \text{ohm} + 4\ \text{ohm}} = 2\ \text{A}
Voltage dividerThe output node is the shared node between two resistors.12 V2 ohm4 ohm2 A+-4 V+-8 Vtopoutputbottom

Compute the two drops

The top resistor drops 4 volts. The bottom resistor drops 8 volts, and that bottom drop is the output voltage.

Vout=Vbottom=8 VV_{\text{out}} = V_{\text{bottom}} = 8\ \text{V}
Voltage dividerThe output marker equals the checked bottom drop.12 V2 ohm4 ohm2 A+-4 V+-8 Vtopoutputbottom

The output is the bottom share

Keep the source at 12 volts. The output follows the fraction of total resistance below the output node. The diagram shows the middle row.

VinRtRbIVtVout12 V1 ohm3 ohm3 A3 V9 V12 V2 ohm4 ohm2 A4 V8 V12 V3 ohm3 ohm2 A6 V6 V\begin{array}{c|c|c|c|c|c}V_{\text{in}}&R_t&R_b&I&V_t&V_{\text{out}}\\12\ \text{V}&1\ \text{ohm}&3\ \text{ohm}&3\ \text{A}&3\ \text{V}&9\ \text{V}\\12\ \text{V}&2\ \text{ohm}&4\ \text{ohm}&2\ \text{A}&4\ \text{V}&8\ \text{V}\\12\ \text{V}&3\ \text{ohm}&3\ \text{ohm}&2\ \text{A}&6\ \text{V}&6\ \text{V}\\\end{array}
Voltage dividerThe middle table row is the checked diagram.12 V2 ohm4 ohm2 A+-4 V+-8 Vtopoutputbottom