Power is only accepted from a cited output voltage and packet current. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Output power first cites voltage and packet current

The power row is downstream of a phase-derived output voltage and a packet-derived average current.

Vout=4 VIavg=12 AV_{\text{out}}=4\ \text{V}\quad I_{\text{avg}}=12\ \text{A}
Output power ledgerThe power row cites phase voltage and packet current.Vout 4 VIavg 12 APout 48 W

More packet current gives proportionally more output power

The output voltage stays at the split midpoint while the packet clock changes current.

IavgVoutPout6 A4 V24 W12 A4 V48 W18 A4 V72 W\begin{array}{c|c|c}I_{\text{avg}}&V_{\text{out}}&P_{\text{out}}\\6\ \text{A}&4\ \text{V}&24\ \text{W}\\12\ \text{A}&4\ \text{V}&48\ \text{W}\\18\ \text{A}&4\ \text{V}&72\ \text{W}\\\end{array}

Packet current sets output power only after voltage is cited

Efficiency is not inferred; this row only multiplies a cited output voltage by a cited packet current.

4 V12 A=48 W4\ \text{V}\cdot12\ \text{A}=48\ \text{W}
Output power ledgerThe power row cites phase voltage and packet current.Vout 4 VIavg 12 APout 48 W