voltage-time-sets-current-change - Electronic Circuits XIV: Inductors and Switching Energy Step by Step

A constant inductor voltage over a finite interval fixes the current ramp. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

The ramp starts with one fixed inductance

The inductor is 2 H. A constant voltage over a declared interval gives a finite current change.

V=L{\Delta I\over \Delta t}\quad\Rightarrow\quad \Delta I={V\Delta t\over L}

More voltage gives a larger current change

The inductance and interval stay fixed, so the current-change rows scale with applied voltage.

\begin{array}{c|c|c|c}L&V&\Delta t&\Delta I\\2\ \text{H}&2\ \text{V}&1\ \text{s}&1\ \text{A}\\2\ \text{H}&4\ \text{V}&1\ \text{s}&2\ \text{A}\\2\ \text{H}&6\ \text{V}&1\ \text{s}&3\ \text{A}\\\end{array}

Voltage times time sets the inductor current change

The interval is a declared constant-voltage training interval, so the checked ramp is finite and exact.

\Delta I={V\Delta t\over L}=6\ \text{V}\cdot1\ \text{s}/2\ \text{H}=3\ \text{A}