Ideal output power rows set input-average current by conservation. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Output power sets ideal average input current

The average output voltage is accepted first. Load current then fixes output power and the ideal input-average current.

Pout=VoutIout;Iin(avg)=PoutVinP_{\text{out}}=V_{\text{out}}I_{\text{out}}\quad;\quad I_{\text{in(avg)}}={P_{\text{out}}\over V_{\text{in}}}
Power relation setupThe power check cites the accepted buck output.Vout 3 VIout 4 APout 12 WIin 1 AL 3 HV 9 Vdt 1 sIi 0 AdI 3 AIf 3 AL 3 HV -3 Vdt 3 sIi 3 AdI -3 AIf 0 Asum Vdt 0 V*sgate passVin 12 VD 1/4Vout 3 VVin 12 VVout 3 VIout 4 APout 12 WIin(avg) 1 A

Three load rows connect output power to input average current

Voltage conversion stays fixed. Increasing load current raises output power, then the same power budget sets input average current.

VoutIoutPoutIin(avg)3 V1 A3 W14 A3 V2 A6 W12 A3 V4 A12 W1 A\begin{array}{c|c|c|c}V_{\text{out}}&I_{\text{out}}&P_{\text{out}}&I_{\text{in(avg)}}\\3\ \text{V}&1\ \text{A}&3\ \text{W}&\tfrac{1}{4}\ \text{A}\\3\ \text{V}&2\ \text{A}&6\ \text{W}&\tfrac{1}{2}\ \text{A}\\3\ \text{V}&4\ \text{A}&12\ \text{W}&1\ \text{A}\\\end{array}

The input-current row comes from the ideal power budget

The input average is not a switch waveform claim; it is the ideal power balance divided by the input voltage.

Iin(avg)=12 W12 V=1 AI_{\text{in(avg)}}={12\ \text{W}\over 12\ \text{V}}=1\ \text{A}
Power input-current accepted rowThe power row is bound to the accepted buck output.Vout 3 VIout 4 APout 12 WIin 1 AL 3 HV 9 Vdt 1 sIi 0 AdI 3 AIf 3 AL 3 HV -3 Vdt 3 sIi 3 AdI -3 AIf 0 Asum Vdt 0 V*sgate passVin 12 VD 1/4Vout 3 VVin 12 VVout 3 VIout 4 APout 12 WIin(avg) 1 A