Active region is not a valid digital output state. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

A weak input produces only a half-ampere of base drive

The input is 3 V, so after the 1 V drop the base current is 1/2 A.

IB=3 V1 V4 Ω=12 AI_B={3\ \text{V} - 1\ \text{V}\over 4\ \Omega}={1\over 2}\ \text{A}
Weak inputThe base-drive check feeds the collector check.input 3 Vdrop 1 Vbase 1/2 Adrive 3/2 Aload 3 Acollector 3/2 Aoutput 6 VactiveMIDDLE

Active region is not a valid digital output claim

The active-region collector current is 3/2 A, leaving the output at 6 V; the state is MIDDLE.

IC=32 A,Vout=6 VMIDDLEI_C={3\over 2}\ \text{A},\quad V_\text{out}=6\ \text{V}\Rightarrow \text{MIDDLE}
Analog middleThe lesson refuses a digital HIGH/LOW label here.input 3 Vdrop 1 Vbase 1/2 Adrive 3/2 Aload 3 Acollector 3/2 Aoutput 6 VactiveMIDDLE