Base currents add, and equality to the driver limit still passes. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Four half-ampere bases need two amperes

Four transistor bases at 1/2 A each sum to 2 A, below the 3 A driver limit.

412 A=2 A3 A4\cdot {1\over 2}\ \text{A}=2\ \text{A}\le 3\ \text{A}
Four-base budgetThe budget status is pass because the sum is below the limit.base 1/2 Abase 1/2 Abase 1/2 Abase 1/2 Atotal 2 Alimit 3 Apass

Equality also passes by the stated convention

Six half-ampere bases sum exactly to the 3 A limit, and equality is accepted.

612 A=3 A6\cdot {1\over 2}\ \text{A}=3\ \text{A}
Equality budgetThe checked pass/fail rule is total current <= limit.base 1/2 Abase 1/2 Abase 1/2 Abase 1/2 Abase 1/2 Abase 1/2 Atotal 3 Alimit 3 Apass