A same-phase divider shows load voltage falling as source impedance grows. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

A small source impedance leaves three quarters on the load

Source impedance 2 ohms and load impedance 6 ohms put 3/4 of the input on the load.

1668=1216\cdot {6\over 8}=12
Source impedance scan rowThe load marker equals the checked voltage share.2 ohm6 ohmV12 V+-4 V+-12 Vsame-phase

Equal source and load split the input

Raising source impedance to 6 ohms makes the load share 1/2 and output 8 volts.

16612=816\cdot {6\over 12}=8
Source impedance scan rowThe same load now receives half the source.6 ohm6 ohmV8 V+-8 V+-8 Vsame-phase

A large source impedance leaves one quarter on the load

Source impedance 18 ohms with the same load leaves share 1/4 and output 4 volts.

16624=416\cdot {6\over 24}=4
Source impedance scan rowThe source impedance is the changed denominator part.18 ohm6 ohmV4 V+-12 V+-4 Vsame-phase