Source and load impedances divide voltage only in the checked same-phase case. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Same-phase impedances form a checked divider

Source impedance 2 ohms and load impedance 6 ohms put 6 parts out of 8 on the load.

ZLZS+ZL=68{Z_L \over Z_S+Z_L}={6\over 8}
Impedance dividerThe mode, components, and voltage markers are checked.2 ohm6 ohmV12 V+-4 V+-12 Vresistive

The load voltage follows the divider

Input 16 volts gives load voltage 12 volts and source drop 4 volts.

1668=1216\cdot {6\over 8}=12
Load voltageThe load marker equals the exact divider result.2 ohm6 ohmV12 V+-4 V+-12 Vresistive