An inverting op-amp output follows from the input current through feedback resistance. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

The input resistor sets the current

The input is 2 volts across 2 ohms, so the input-resistor current is 1 ampere.

I=2 V2 ohm=1 AI = \frac{2\ \text{V}}{2\ \text{ohm}} = 1\ \text{A}
Input currentThe inverting node is checked as virtual ground.+-op amprails -12 V to 12 VVout -6 VV+ 0 VV- 0 VI+ 0 AI- 0 ARin 2 ohmIin 1 ARf 6 ohmIf 1 AV+ = V-inverting

The output moves negative through the feedback resistor

The same current through 6 ohms requires -6 volts at the output.

Vout=(1 A)6 ohm=6 VV_{\text{out}} = -\left(1\ \text{A}\right)\cdot 6\ \text{ohm} = -6\ \text{V}
Inverting gainThe output sign is checked by feedback current balance.+-op amprails -12 V to 12 VVout -6 VV+ 0 VV- 0 VI+ 0 AI- 0 ARin 2 ohmIin 1 ARf 6 ohmIf 1 AV+ = V-inverting