A polarizer passes only the field component along its transmission axis, so the surviving amplitude is E0 * cos(theta). This is an ideal projection: the polarizer is perfect, the input field is a single clean vector, and the axis angle is known exactly. Real polarizers leak, absorb, and misalign, so cos(theta) is a model for the stated inputs, not a measurement.

A linear polarizer keeps the requested axis field component and blocks the orthogonal one. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

An ideal polarizer keeps the axis component

For axis mode, the incoming 10 volts per metre splits with factor 3/5 for the passed component and orthogonal remainder.

E∥=10 V/m⋅35=6 V/m,E⊥=10 V/m⋅45=8 V/mE_{\parallel}=10\ \text{V}/\text{m}\cdot\frac{3}{5}=6\ \text{V}/\text{m},\quad E_{\perp}=10\ \text{V}/\text{m}\cdot\frac{4}{5}=8\ \text{V}/\text{m}
Projection by axis componentThe polarizer keeps the projected component by exact factor.incidentField=10 V/maxisMode=three-four-fiveparallelFactor=3/5parallelField=6 V/mperpendicularField=8 V/macceptedBit=1 bit