A three-row scan holds the polarization relation fixed and varies the field amplitude across rows, showing how the intensity (proportional to amplitude squared) moves through the ledger at one stated amplitude per row. The arithmetic is exact only for the stated rows and inputs in the ideal polarization model. Real beams add finite bandwidth, imperfect polarization, alignment error, detector calibration, and measurement uncertainty.

Holding wave speed fixed while magnetic amplitude changes makes E=cB readable. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

One tesla gives six volts per metre

Hold the training speed at 6 metres per second. With magnetic amplitude 1 tesla, the electric amplitude is 6 volts per metre.

E=cB=6 m/s⋅1 T=6 V/mE=cB=6\ \text{m}/\text{s}\cdot1\ \text{T}=6\ \text{V}/\text{m}
Field amplitude scan rowThe checked wave row binds speed, B, and E.speed=6 m/smagneticField=1 TelectricField=6 V/mwavelength=3 mfrequency=2 Hz

Two tesla doubles the electric field

Only the magnetic amplitude changes to 2 tesla. The same speed makes the electric field 12 volts per metre.

E=6 m/s⋅2 T=12 V/mE=6\ \text{m}/\text{s}\cdot2\ \text{T}=12\ \text{V}/\text{m}
Field amplitude scan rowThe B row doubles and E doubles with it.speed=6 m/smagneticField=2 TelectricField=12 V/mwavelength=3 mfrequency=2 Hz

Three tesla makes eighteen volts per metre

The third row changes magnetic amplitude to 3 tesla and closes at 18 volts per metre. Three rows make the proportional relation scannable.

E=6 m/s⋅3 T=18 V/mE=6\ \text{m}/\text{s}\cdot3\ \text{T}=18\ \text{V}/\text{m}
Field amplitude scan rowThe final checked row keeps E over B equal to speed.speed=6 m/smagneticField=3 TelectricField=18 V/mwavelength=3 mfrequency=2 Hz