The power spent in the series resistors adds to the power delivered by the battery.
Example
The power spent in the series resistors adds to the power delivered by the battery. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.
highlighted = computed this step
Power is voltage drop times current
Each resistor turns electrical energy into heat. Its power is the voltage drop across it times the current through it.
P=VI
At the same current, bigger drops make more power
Hold current at 2 amperes. More voltage drop means each coulomb spends more energy, so the resistor heats at a larger power.
V2V4V8VI2A2A2AP4W8W16W
At the same drop, bigger current makes more power
Now hold one resistor's drop at 4 volts and scan the current. More coulombs per second means more energy spent each second.
V4V4V4VI1A2A3AP4W8W12W
Compute each resistor power
Ra uses 8 watts and Rb uses 16 watts.
partRaRbV4V8VI2A2AP8W16W
The resistor powers add to the battery output
The two resistor powers add to 24 watts, the same power delivered by the battery.
PRa+PRb=8W+16W=24W
electricityEach resistor spends part of the battery's power output, and the resistor powers add to the source power.