A mixed circuit is reduced in stages: equal parallel branches first, then the remaining series resistance. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

A mixed circuit has one part before a split

Current first passes through the series resistor, then reaches a junction where it can split into two equal branch resistors.

series part+parallel part\text{series part} + \text{parallel part}
Mixed series-parallel circuitA source drives a series resistor before two equal parallel branches.12 VA3 A2 ohm4 ohm4 ohm3 A

Reduce the equal parallel pair

The two equal branch resistors share the same endpoints. For equal branches, the pair acts like half one branch resistance.

R=Rbranch2=2 ohmR_{\parallel} = \frac{R_{\text{branch}}}{2} = 2\ \text{ohm}

Scan three mixed networks

Keep the source at 12 volts. Each row reduces the equal parallel pair, adds the series resistor, then reads the total current.

RsRbranchRReqI2 ohm4 ohm2 ohm4 ohm3 A2 ohm2 ohm1 ohm3 ohm4 A2 ohm8 ohm4 ohm6 ohm2 A\begin{array}{c|c|c|c|c}R_{\text{s}}&R_{\text{branch}}&R_{\parallel}&R_{\text{eq}}&I\\2\ \text{ohm}&4\ \text{ohm}&2\ \text{ohm}&4\ \text{ohm}&3\ \text{A}\\2\ \text{ohm}&2\ \text{ohm}&1\ \text{ohm}&3\ \text{ohm}&4\ \text{A}\\2\ \text{ohm}&8\ \text{ohm}&4\ \text{ohm}&6\ \text{ohm}&2\ \text{A}\\\end{array}
Mixed series-parallel circuitThe diagram is the first row of the checked scan.12 VA3 A2 ohm4 ohm4 ohm3 A

Add series resistance after reducing the split

For the shown circuit, the equivalent resistance is 4 ohm.

Req=2 ohm+2 ohm=4 ohmR_{\text{eq}} = 2\ \text{ohm} + 2\ \text{ohm} = \hl{4}\ \text{ohm}

Use the equivalent resistance for source current

The source current is 3 amperes. The equivalent one-resistor picture and the mixed topology therefore agree.

I=12 V4 ohm=3 AI = \frac{12\ \text{V}}{4\ \text{ohm}} = \hl{3}\ \text{A}
Equivalent source currentThe reduced circuit has the same source current as the mixed circuit.12 VA3 A4 ohm3 A

The voltage budget still closes

The series resistor drops 6 volts and the branch pair drops 6 volts. Those drops use the full source budget.

Vs+V=6 V+6 V=12 VV_{\text{s}} + V_{\parallel} = 6\ \text{V} + 6\ \text{V} = \hl{12}\ \text{V}
Mixed voltage budgetVoltage markers show the series drop plus the branch-pair drop.12 VA3 A2 ohm4 ohm4 ohm3 A+-6 V+-6 V