An electric field tells how much force a positive test charge would feel per coulomb at a point.
Example
An electric field tells how much force a positive test charge would feel per coulomb at a point. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.
highlighted = computed this step
Use a test charge
Place a small positive test charge at the point where you want to know the electric field. Here the test charge is 3 coulombs.
qtest=3C
Measure force on the test charge
The force on that test charge is 12 newtons. The electric field is force per coulomb, so divide the force by the test charge.
E=qtestF
Compute force per charge
Divide 12 newtons by 3 coulombs. The result is 4 newtons per coulomb.
E=3C12N=4N/C
More force gives more field at fixed charge
Hold the test charge at 3 coulombs. The diagram shows the middle row; increasing force increases the field by the same factor.
F6N12N18Nqtest3C3C3CE2N/C4N/C6N/C
More test charge lowers force per charge
Now hold the force at 12 newtons and change the test charge. A larger test charge spreads the same force over more coulombs, so the field value is smaller.
F12N12N12Nqtest2C3C6CE6N/C4N/C2N/C
electrostaticsA field vector is a local force-per-charge claim at one point.