Stored energy grows with voltage squared when capacitance is fixed, so doubling voltage makes four times the energy. This pattern is exact for an ideal capacitor below its limits; real devices have breakdown ratings, dielectric losses, changing capacitance, heat limits, leakage, and measurement uncertainty.

Stored energy is proportional to voltage squared at fixed capacitance. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Start with the base energy

At 6 volts, the stored energy is 36 joules.

Ubase=36 JU_{\text{base}} = 36\ \text{J}
Base stored energyThe base capacitor value is checked by the helper.2 F

Double voltage

Raise the voltage to 12 volts while keeping capacitance the same.

Vchanged=12 VV_{\text{changed}} = 12\ \text{V}
Changed stored energyThe changed capacitor uses the same capacitance.2 F

Energy scales with voltage squared

Because voltage is squared, doubling voltage multiplies stored energy by 4. The new energy is 144 joules.

Uchanged=4⋅36 J=144 JU_{\text{changed}} = 4\cdot 36\ \text{J} = 144\ \text{J}
Changed stored energyThe changed capacitor uses the same capacitance.2 F

Squaring voltage bends the pattern

Hold capacitance fixed. Doubling voltage from three to six makes four times the energy; doubling again from six to twelve does the same.

CVQU2 F3 V6 C9 J2 F6 V12 C36 J2 F12 V24 C144 J\begin{array}{c|c|c|c}C&V&Q&U\\2\ \text{F}&3\ \text{V}&6\ \text{C}&9\ \text{J}\\2\ \text{F}&6\ \text{V}&12\ \text{C}&36\ \text{J}\\2\ \text{F}&12\ \text{V}&24\ \text{C}&144\ \text{J}\\\end{array}
Changed stored energyThe last table row is the changed checked diagram.2 F