Stress can be read backward as the force required for a chosen area. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Stress and area can be inverted to recover force

Start from target stress 6 Pa and checked area 2 square meters then multiply them to recover the force 12 N. The diagram must show that same force-area-stress triple.

F=σA=6 Pa×2 m2=12 NF=\sigma A=6\ \text{Pa}\times2\ \text{m}^{2}=12\ \text{N}
Stress inversion rowThe displayed force equals stress times area.forceareaforce=12 Narea=2 m^2stress=6 Pa

Stress and area can be inverted to recover force

Start from target stress 5 Pa and checked area 4 square meters then multiply them to recover the force 20 N. The diagram must show that same force-area-stress triple.

F=σA=5 Pa×4 m2=20 NF=\sigma A=5\ \text{Pa}\times4\ \text{m}^{2}=20\ \text{N}
Stress inversion rowThe displayed force equals stress times area.forceareaforce=20 Narea=4 m^2stress=5 Pa

Stress and area can be inverted to recover force

Start from target stress 8 Pa and checked area 5 square meters then multiply them to recover the force 40 N. The diagram must show that same force-area-stress triple.

F=σA=8 Pa×5 m2=40 NF=\sigma A=8\ \text{Pa}\times5\ \text{m}^{2}=40\ \text{N}
Stress inversion rowThe displayed force equals stress times area.forceareaforce=40 Narea=5 m^2stress=8 Pa