Bulk response uses positive pressure and volume-change magnitudes. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Bulk response starts from volume and volume change

The book uses positive compression magnitudes. Volume and volume change are checked before pressure is accepted.

V=6 m3ΔV=1 m3V=6\ \text{m}^{3}\qquad \Delta V=1\ \text{m}^{3}
Bulk response inputsPressure follows a checked volume-change ratio.pressurevolume changevolume=6 m^3volumeChange=1 m^3pressureChange=2 Pamodulus=12 Pa

Pressure follows the volume-change ratio

Hold the starting volume and bulk modulus fixed. The pressure column follows the checked volume change.

VΔVKΔP6 m312 m312 Pa1 Pa6 m31 m312 Pa2 Pa6 m32 m312 Pa4 Pa\begin{array}{c|c|c|c}V&\Delta V&K&\Delta P\\6\ \text{m}^{3}&\tfrac{1}{2}\ \text{m}^{3}&12\ \text{Pa}&1\ \text{Pa}\\6\ \text{m}^{3}&1\ \text{m}^{3}&12\ \text{Pa}&2\ \text{Pa}\\6\ \text{m}^{3}&2\ \text{m}^{3}&12\ \text{Pa}&4\ \text{Pa}\\\end{array}

Bulk modulus turns volume strain into pressure change

This checked ledger uses positive compression magnitudes; sign conventions are outside this training surface.

ΔP=KΔVV=12 Pa1 m36 m3=2 Pa\Delta P=K\frac{\Delta V}{V}=12\ \text{Pa}\cdot\frac{1\ \text{m}^{3}}{6\ \text{m}^{3}}=2\ \text{Pa}
Bulk modulus ledgerVolume strain and pressure change are checked magnitudes.pressurevolume changevolume=6 m^3volumeChange=1 m^3pressureChange=2 Pamodulus=12 Pa