Spatial Boundary Depth Scans

Occupancy Ceiling Three-Row Scan

Seen hits bracket a ceiling while occupancy fractions stay exact. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Four seen hits stay below the ceiling

Raw hits 6 split into seen 4 and masked 2 against capacity 8.

m=Nmax⁡−Ns=6−4=2, o=1/2m=N_{\max}\mathbin{-}N_s=6\mathbin{-}4=2,\ o=1/2
Hit occupancySeen hits are counted against channel capacity.raw=6 countseen=4 countmasked=2 countcapacity=8 countrawHits=6 countseenHits=4 countmaskedHits=2 countcapacity=8 countoccupancyFraction=1/2 ratio

Six seen hits land on the ceiling

Raw hits 8 split into seen 6 and masked 2 against capacity 8.

m=Nmax⁡−Ns=6−6=0, o=3/4m=N_{\max}\mathbin{-}N_s=6\mathbin{-}6=0,\ o=3/4
Hit occupancySeen hits are counted against channel capacity.raw=8 countseen=6 countmasked=2 countcapacity=8 countrawHits=8 countseenHits=6 countmaskedHits=2 countcapacity=8 countoccupancyFraction=3/4 ratio

Eight seen hits exceed the ceiling

Raw hits 9 split into seen 8 and masked 1 against capacity 8.

m=Nmax⁡−Ns=6−8=−2, o=1m=N_{\max}\mathbin{-}N_s=6\mathbin{-}8=-2,\ o=1
Hit occupancySeen hits are counted against channel capacity.raw=9 countseen=8 countmasked=1 countcapacity=8 countrawHits=9 countseenHits=8 countmaskedHits=1 countcapacity=8 countoccupancyFraction=1 ratio