Implement queue behavior with an input stack and an output stack.

Algorithm

Basic Implementation

basic.dart
String render(List<int> values) => values.join(' -> ');

void main() {
  final inStack = <int>[];
  final outStack = <int>[];
  for (final value in [10, 20, 30]) { inStack.add(value); }
  while (inStack.isNotEmpty) { outStack.add(inStack.removeLast()); }
  final removed = <int>[];
  while (outStack.isNotEmpty) { removed.add(outStack.removeLast()); }
  print(render(removed));
}

The two-stack queue keeps cheap enqueues in the input stack, then reverses that stack only when dequeue needs the output stack.

Step 1 - Enqueue pushes onto the input stack

After enqueueing 10, 20, 30, the newest input value is on top of the input stack.

After enqueues: input top is 30; output is empty.input stack top -> bottomoutput stack top -> bottomremoved30(empty)(empty)2010

Step 2 - Transfer reverses into output order

Moving every input value to the output stack turns 10 into the next pop.

After transfer: output top is 10, so dequeue returns the oldest value.input stackoutput stack top -> bottomremoved(empty)10(empty)2030

Step 3 - Dequeue pops from output

The output stack pops 10 first while 20 becomes the next front.

After one dequeue: removed is 10; output top is now 20.input stackoutput stack top -> bottomremoved(empty)201030

Complexity

  • Time: O(1) amortized per operation
  • Space: O(n)

Implementation notes

  • Keep the explicit stack/queue operations. Library shortcuts that only produce the final list hide the data-structure behavior this lesson is meant to replay.
  • The final output uses a deterministic a -> b -> c format for cross-language comparison.
input stack Enqueue pushes new values onto the input stack.
output stack When the output stack is empty, transferring all input values reverses them into dequeue order.