Graphs
Shortest Path (Unweighted, via BFS)
BFS explores a graph layer by layer, so the first time it reaches a vertex
is along a shortest path. Track dist[v] and parent[v] while exploring,
then walk parents back from the target to reconstruct the route.
Algorithm
On the canonical graph from graph-adjacency-list, the shortest path from
1 to 6 is [1, 2, 4, 5, 6] with distance 4. The path is rebuilt from
parent: 6 -> 5 -> 4 -> 2 -> 1, reversed.
Basic Implementation
basic.cpp
#include <iostream>
#include <vector>
#include <map>
#include <queue>
int main() {
std::map<int, std::vector<int>> adj;
adj[1] = {2, 3};
adj[2] = {1, 4};
adj[3] = {1, 4};
adj[4] = {2, 3, 5};
adj[5] = {4, 6};
adj[6] = {5};
int src = 1;
int dst = 6;
std::map<int, int> dist;
std::map<int, int> parent;
dist[src] = 0;
parent[src] = 0;
std::queue<int> q;
q.push(src);
while (!q.empty()) {
int v = q.front();
q.pop();
for (int nb : adj[v]) {
if (dist.find(nb) == dist.end()) {
dist[nb] = dist[v] + 1;
parent[nb] = v;
q.push(nb);
}
}
}
std::vector<int> path;
int node = dst;
while (node != 0) {
path.push_back(node);
node = parent[node];
}
std::cout << "[";
for (size_t i = 0; i < path.size(); ++i) {
if (i > 0) std::cout << ", ";
std::cout << path[path.size() - 1 - i];
}
std::cout << "]" << std::endl;
std::cout << dist[dst] << std::endl;
return 0;
}
Complexity
- Time: O((V + E) log V) in this C++ source because
std::maplookups and insertions are ordered-tree operations - Space: O(V)
Implementation notes
- In C++, the adjacency list is a
std::map<int, std::vector<int>>, so each vertex maps to a vector of neighbourintvalues in the order written inbasic.cpp. std::map<int, int> distis both the distance table and the visited check viadist.find(nb) == dist.end().parentstores predecessor ids, with0as the source sentinel used by the reconstruction loop. These map operations are ordered lookups, not average O(1) hash-table probes.std::queue<int>stores copied vertex ids; the code usesfront(),pop(), andpush(nb)while mutatingdistandparentonly when a neighbour is first discovered.- The replayed queue states are
[2, 3],[3, 4],[4],[5],[6], and[], withdist[6]ending at4andparent[6]set to5. - Path reconstruction pushes
6, 5, 4, 2, 1into astd::vector<int> pathand prints it in reverse index order as[1, 2, 4, 5, 6], followed bydist[dst]on the next line. - Visible allocation is the map nodes, adjacency/path vectors, and queue
storage; visible mutation is distance/parent insertion, queue updates, and
path.push_back. The trace's weighted contrast shows the limit: this BFS path minimizes edge count, not total edge weight.
layers equal distance
BFS order equals distance in an unweighted graph.