Arrays and Iteration
Two-Sum with Hash Lookup
Walk the array once, storing seen values in a lookup table. When the complement is already present, the result indices are known.
Algorithm
Basic Implementation
basic.cpp
#include <iostream>
#include <unordered_map>
#include <vector>
int main() {
std::vector<int> arr{2, 7, 11, 4, 5};
int target = 9;
std::unordered_map<int, int> seen;
int first = -1;
int second = -1;
for (int i = 0; i < static_cast<int>(arr.size()); ++i) {
int need = target - arr[i];
auto it = seen.find(need);
if (it != seen.end()) {
first = it->second;
second = i;
break;
}
seen[arr[i]] = i;
}
std::cout << "[" << first << ", " << second << "]\n";
return 0;
}
Complexity
- Time: O(n) average
- Space: O(n)
Implementation notes
- In C++, the input is a
std::vector<int>initialized as{2, 7, 11, 4, 5}and the lookup table isstd::unordered_map<int, int>, mapping a seen value to its earlier index. - The loop index is an
intand compares againststatic_cast<int>(arr.size()); eacharr[i]read stays inside the vector bounds used by the trace. int need = target - arr[i]computes the complement, andseen.find(need)checks without inserting a missing key. Onlyseen[arr[i]] = imutates the hash table after a miss.- The trace records
{}at start, then a miss for need7and insert{2: 0}, then a hit for need2ati=1, producing result[0, 1]. firstandsecondare scalarintresult slots initialized to-1; the source prints them withstd::cout << "[" << first << ", " << second << "]\n".- Visible allocation is the vector storage and unordered-map buckets/nodes. The source does not reserve buckets or expose collision behavior in the replay, so the trace shows logical lookup state rather than bucket layout.
execution replay
The checked-in replay follows the language-neutral state table for `array-two-sum-hash`.
cross-language comparison
This C++ DSA version keeps the same data and final output as every other DSA book in this wave.