The capacitor equation is solved forward and backward so charge, voltage, and capacitance are seen as one exact unit ledger.
Example
The capacitor equation is solved forward and backward so charge, voltage, and capacitance are seen as one exact unit ledger. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.
highlighted = computed this step
One capacitor equation can be read three ways
The same ideal-capacitor relation can solve for charge, voltage, or capacitance. The middle checked case uses 3 farads and 4 volts, which gives 12 coulombs.
Q=CV,V=CQ,C=VQ
Forward reading: capacitance times voltage gives charge
Read the first table left to right. Each row multiplies capacitance by voltage to close the charge column.
C2F3F4FV3V4V5VQ6C12C20C
Inverse reading: charge divided by capacitance gives voltage
Now hold charge at 12 coulombs and divide by three different capacitances. The same equation is being read from charge back to voltage.
Q12C12C12CC2F3F4FV6V4V3V
Inverse reading: charge divided by voltage gives capacitance
Finally divide charge by voltage. Three rows with matching ratios all recover the same 3 farad capacitance.
Q12C18C24CV4V6V8VC3F3F3F
The unit algebra closes the three readings
Coulombs per volt returns farads, and coulombs per farad returns volts. This is why the three table readings are one equation, not three separate rules.
VC=FFC=VF⋅V=C
capacitorsUse three scan tables to read Q = C V as charge, voltage, and capacitance.