Linked Structures
Delete by Value
Find the node before the target value and rewire its next pointer so the target node leaves the chain.
Algorithm
The replay labels nodes by value, such as node(20), and never exposes object
identity or memory addresses. This C DSA implementation uses the
same small chain as the rest of the DSA track.
Basic Implementation
basic.c
#include <stdio.h>
#include <stdlib.h>
typedef struct Node {
int value;
struct Node* next;
} Node;
Node* node(int value, Node* next) {
Node* n = malloc(sizeof(Node));
n->value = value;
n->next = next;
return n;
}
void print_chain(Node* head) {
Node* cursor = head;
while (cursor != NULL) {
printf("%d -> ", cursor->value);
cursor = cursor->next;
}
printf("null\n");
}
int main(void) {
Node* head = node(10, node(20, node(30, node(40, NULL))));
int target = 30;
Node* cursor = head;
while (cursor->next != NULL) {
if (cursor->next->value == target) {
cursor->next = cursor->next->next;
break;
}
cursor = cursor->next;
}
print_chain(head);
return 0;
}
Complexity
- Time: O(n)
- Space: O(1)
Implementation notes
- Keep the explicit node and pointer/reference operations; array shortcuts hide the linked-list state this lesson is meant to replay.
- The final output prints the chain in a deterministic
a -> b -> nullform for cross-language comparison.
predecessor
Deletion needs the node before the one being removed.
rewiring
The predecessor skips the target and points at the target's next node.