Coherent bucket size sets the visible transverse fraction. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Visible transverse signal is the coherent bucket

The initial bucket stays fixed; the scan changes how much remains coherent.

FT=coherentinitialF_T={\text{coherent}\over \text{initial}}
Transverse fraction rowThe visible fraction is coherent bucket divided by initial bucket.initial 12coherent 6fraction 1/2

Three coherent buckets give three visible fractions

The dephased bucket is the complement that keeps the initial total closed.

coherentdephasedFTvisible391436612693349\begin{array}{c|c|c|c}\text{coherent}&\text{dephased}&F_T&\text{visible}\\3&9&\frac{1}{4}&3\\6&6&\frac{1}{2}&6\\9&3&\frac{3}{4}&9\\\end{array}

The middle row keeps one half visible

This is still a toy bucket fraction, not a fitted decay constant.

6/12=126/12=\frac{1}{2}
Transverse fraction rowThe visible fraction is coherent bucket divided by initial bucket.initial 12coherent 6fraction 1/2