BFS explores a graph layer by layer, so the first time it reaches a vertex is along a shortest path. Track dist[v] and parent[v] while exploring, then walk parents back from the target to reconstruct the route.

Algorithm

On the canonical graph from graph-adjacency-list, the shortest path from 1 to 6 is [1, 2, 4, 5, 6] with distance 4. The path is rebuilt from parent: 6 -> 5 -> 4 -> 2 -> 1, reversed.

Basic Implementation

basic.sh
#!/usr/bin/env bash
set -euo pipefail
declare -A adj
adj[1]="2 3"
adj[2]="1 4"
adj[3]="1 4"
adj[4]="2 3 5"
adj[5]="4 6"
adj[6]="5"
src=1
dst=6
declare -A dist
declare -A parent
dist[$src]=0
parent[$src]=0
queue=("$src")
head=0
while [ "$head" -lt "${#queue[@]}" ]; do
	v=${queue[head]}
	head=$((head + 1))
	read -ra nbrs <<< "${adj[$v]}"
	for nb in "${nbrs[@]}"; do
		if [ -z "${dist[$nb]+_}" ]; then
			dist[$nb]=$((dist[$v] + 1))
			parent[$nb]=$v
			queue+=("$nb")
		fi
	done
done
path=()
node=$dst
while [ "$node" -ne 0 ]; do
	path+=("$node")
	node=${parent[$node]}
done
printf '['
sep=''
for ((k = ${#path[@]} - 1; k >= 0; k--)); do
	printf '%s%d' "$sep" "${path[k]}"
	sep=', '
done
printf ']\n'
printf '%d\n' "${dist[$dst]}"

Complexity

  • Time: O(V + E)
  • Space: O(V)

Implementation notes

  • Bash: a dist associative array doubles as the visited check, parent records predecessors (0 marks the source), and a head index walks the queue array.
  • The replay shows dist, parent, and the queue filling in, then the reconstructed path, matching the lesson spec.
layers equal distance BFS order equals distance in an unweighted graph.